Difference between revisions of "Calculus"

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(Created page with "== Limits == Definition of a limit: <math>\lim_{x \rightarrow c} f(x) = L\,</math> means that for all real values of <math>\epsilon > 0 \,</math>, there exists <math>\delta...")
 
(Limits)
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Now, if we want to prove that it is L, we have to look at ''all'' possible numbers, especially small ones. Now, let's choose a number x that is awfully close to c, and see what f(c) gives us. It should get use well below this number we imagined.
 
Now, if we want to prove that it is L, we have to look at ''all'' possible numbers, especially small ones. Now, let's choose a number x that is awfully close to c, and see what f(c) gives us. It should get use well below this number we imagined.
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=== Example ===
  
 
As a simple example, let's find:
 
As a simple example, let's find:
  
<math>\lim_{x \rightarrow 0}\frac{1}{x}</math>
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<math>\lim_{x \rightarrow \inf}\frac{1}{x}</math>
  
 
I'm going to assume that the answer (L) is 0.
 
I'm going to assume that the answer (L) is 0.
  
Now, let me choose a super-duper small number, 0.001. Can I find another number (c) close to 0 that will give me <math>|\frac{1}{c} - 0| < 0.001 \,</math>? Of course, I can, and it would be something like 10,000, or anything bigger.
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Now, let me choose a super-duper small number close to 0, 0.001, for <math>\epsilon \,</math>. Can I find another number (x) close to <math>\inf \,</math> that will give me <math>|\frac{1}{x} - 0| < 0.001 \,</math>? Of course, I can, and it would be something like 10,000, or anything bigger.
  
It doesn't matter how close I get to 0, I can always find another number that will get me even closer.
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It doesn't matter how close I get to 0, I can always find another number that will get me even closer. I never have to choose infinity itself, because that's not even a real number, but I can get closer and closer if I need to.
  
 
So the limit is 0.
 
So the limit is 0.

Revision as of 08:10, 14 April 2012

Limits

Definition of a limit:

<math>\lim_{x \rightarrow c} f(x) = L\,</math>

means that for all real values of <math>\epsilon > 0 \,</math>, there exists <math>\delta \,</math> for all <math>x \,</math> such that <math>0 < |x - c| < \delta \,</math>, we have <math>|f(x) - L| < \epsilon \,</math>.

In my own words:

Assume that the limit of <math>\lim_{x \rightarrow c} f(x) \,</math> is L.

Now, if we want to prove that it is L, we have to look at all possible numbers, especially small ones. Now, let's choose a number x that is awfully close to c, and see what f(c) gives us. It should get use well below this number we imagined.

Example

As a simple example, let's find:

<math>\lim_{x \rightarrow \inf}\frac{1}{x}</math>

I'm going to assume that the answer (L) is 0.

Now, let me choose a super-duper small number close to 0, 0.001, for <math>\epsilon \,</math>. Can I find another number (x) close to <math>\inf \,</math> that will give me <math>|\frac{1}{x} - 0| < 0.001 \,</math>? Of course, I can, and it would be something like 10,000, or anything bigger.

It doesn't matter how close I get to 0, I can always find another number that will get me even closer. I never have to choose infinity itself, because that's not even a real number, but I can get closer and closer if I need to.

So the limit is 0.

Derivatives

Integrals

Fundamental Theorem of Calculus

This is simply that the anti-derivative is the integral, as we've already said. This is one of those things that should make you go, "Wow!"